-1-12x^2=-637

Solution for -1-12x^2=-637 equation:

-1-12x^2=-637

We move all terms to the left:

-1-12x^2-(-637)=0

We add all the numbers together, and all the variables

-12x^2+636=0

a = -12; b = 0; c = +636;
Δ = b2-4ac
Δ = 02-4·(-12)·636
Δ = 30528
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{30528}=\sqrt{576*53}=\sqrt{576}*\sqrt{53}=24\sqrt{53}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-24\sqrt{53}}{2*-12}=\frac{0-24\sqrt{53}}{-24}
=-\frac{24\sqrt{53}}{-24}
=-\frac{\sqrt{53}}{-1}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+24\sqrt{53}}{2*-12}=\frac{0+24\sqrt{53}}{-24}
=\frac{24\sqrt{53}}{-24}
=\frac{\sqrt{53}}{-1}
$